x^2+10x-6375=0

Solution for x^2+10x-6375=0 equation:

x^2+10x-6375=0

a = 1; b = 10; c = -6375;
Δ = b2-4ac
Δ = 102-4·1·(-6375)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-160}{2*1}=\frac{-170}{2}
=-85
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+160}{2*1}=\frac{150}{2}
=75
$